A=
AP=<t><c></t>
C0=V11
C1=V12
C2=V13
C3=V14
C4=
C5=
C6=
C7=
C8=
C9=
ES=Answers may vary.
F0=
F1=
F2=
H=$.hint$
INST=
M1=
M2=
M3=
M4=
M5=
M6=
M7=
M8=
M9=
MS=1
MW1=
MW2=
MW3=
MW4=
MW5=
MW6=
MW7=
MW8=
MW9=
N=
Q=Do the multiplication V0 &times; V2 using the Egyptian method of successive duplication.
SA=Answers may vary.
T=M
TF=-1
TL=
TOL=+1E-4
U=NOUNIT
V0=I[10,30]
V1=I[1,4]
V10=S"<fc=3>1</fc>&nbsp;&nbsp;&nbsp;<fc=5>V0</fc><div><fc=3>2</fc>&nbsp;&nbsp;&nbsp;<fc=5>V3</fc></div><div>V2&nbsp;&nbsp;&nbsp;V6</div>"
V11=L[V1:V10,V9,V8,V7]
V12=L[V1:V7,V10,V9,V8]
V13=L[V1:V8,V7,V10,V9]
V14=L[V1:V9,V8,V7,V10]
V2=I(9)
V3=I(2*V0)
V4=I(4*V0)
V5=I(8*V0)
V6=I(V0*V2)
V7=S"<fc=3>1</fc>&nbsp;&nbsp;&nbsp;<fc=5>V0</fc><div>2&nbsp;&nbsp;&nbsp;V3</div><div>4&nbsp;&nbsp;&nbsp;V4</div><div><fc=3>8</fc>&nbsp;&nbsp;&nbsp;<fc=5>V5</fc></div><div>V2&nbsp;&nbsp;&nbsp;V6</div>"
V8=S"1&nbsp;&nbsp;&nbsp;V0<div><fc=3>2</fc>&nbsp;&nbsp;&nbsp;<fc=5>V3</fc></div><div><fc=3>4</fc>&nbsp;&nbsp;&nbsp;<fc=5>V4</fc></div><div>V2&nbsp;&nbsp;&nbsp;V6</div>"
V9=S"<fc=3>1</fc>&nbsp;&nbsp;&nbsp;<fc=5>V0</fc><div>2&nbsp;&nbsp;&nbsp;V3</div><div><fc=3>4</fc>&nbsp;&nbsp;&nbsp;<fc=5>V4</fc></div><div>V2&nbsp;&nbsp;&nbsp;V6</div>"
W=<ostep=p>(V2==9)::\n<font color=blue><fc=3>1</fc></font>::&nbsp;&nbsp;&nbsp;::<fc=5>V0</fc>::&nbsp;\n</ostep>\n<ostep=p>(V2==9)::\n2::&nbsp;&nbsp;&nbsp;::V3::&nbsp;\n</ostep>\n<ostep=p>(V2==9)::\n4::&nbsp;&nbsp;&nbsp;::V4::&nbsp;\n</ostep>\n<ostep>(V2==9)::\n<fc=3><box>8</box></fc>::&nbsp;&nbsp;&nbsp;::<fc=5>V5</fc>::&nbsp;\n</ostep>\n<ostep>(V2==9)::\nTotal{    }V2::&nbsp;&nbsp;&nbsp;::<box>V6</box>::$arrowleft$ Answer\n</ostep>\n<!--     //     -->\n<!--     //for 6     -->\n<ostep=p>(V2==6)::\n1::&nbsp;&nbsp;&nbsp;::V0::&nbsp;\n</ostep>\n<ostep=p>(V2==6)::\n<fc=3>2</fc>::&nbsp;&nbsp;&nbsp;::<fc=5>V3</fc>::&nbsp;\n</ostep>\n<ostep>(V2==6)::\n<fc=3><box>4</box></fc>::&nbsp;&nbsp;&nbsp;::<fc=5>V4</fc>::&nbsp;\n</ostep>\n<ostep>(V2==6)::\nTotal{    }V2::&nbsp;&nbsp;&nbsp;::<box>V6</box>::$arrowleft$ Answer\n</ostep>\n<!--     //     -->\n<!--     //for 5     -->\n<ostep=p>(V2==5)::\n<fc=3>1</fc>::&nbsp;&nbsp;&nbsp;::<fc=5>V0</fc>::&nbsp;\n</ostep>\n<ostep=p>(V2==5)::\n2::&nbsp;&nbsp;&nbsp;::V3::&nbsp;\n</ostep>\n<ostep>(V2==5)::\n<fc=3><box>4</box></fc>::&nbsp;&nbsp;&nbsp;::<fc=5>V4</fc>::&nbsp;\n</ostep>\n<ostep>(V2==5)::\nTotal{    }V2::&nbsp;&nbsp;&nbsp;::<box>V6</box>::$arrowleft$ Answer\n</ostep>\n<!--     //     -->\n<!--     //for 3     -->\n<ostep=p>(V2==3)::\n<fc=3>1</fc>::&nbsp;&nbsp;&nbsp;::<fc=5>V0</fc>::&nbsp;\n</ostep>\n<ostep>(V2==3)::\n<fc=3>2</fc>::&nbsp;&nbsp;&nbsp;::<fc=5><box>V3</box></fc>::&nbsp;\n</ostep>\n<ostep>(V2==3)::\nTotal{    }V2::&nbsp;&nbsp;&nbsp;::<box>V6</box>::$arrowleft$ Answer\n</ostep>\n<!--     //     -->\n<step=p>The numbers to be added are only those in red.\n</step>\n
YN=-1
cnum=4
followup=
ilev=0
mcdm=1
mdm=0
mpc=unspecified
mpn=2
mpv=2.0
mwnum=2
ncd=-1
subject=unspecified
varnum=19
commentV0=        // just use number
commentV10=        //for 3
commentV11=          //ans
commentV12=         //dist
commentV13=         //dist
commentV14=           //dist
commentV2= // L[V1:3,5,6,9]          //break into 2s
commentV6=          //ans
commentV7=        //for 9
commentV8=        //for 6
commentV9=        //for 5