A=
AP=<t><c></t>
C0=V8
C1=V9
C2=V10
C3=V4
C4=
C5=
C6=
C7=
C8=
C9=
ES=Answers may vary.
F0=
F1=
F2=
H=$.hint$
INST=
M1=
M2=
M3=
M4=
M5=
M6=
M7=
M8=
M9=
MS=1
MW1=
MW2=
MW3=
MW4=
MW5=
MW6=
MW7=
MW8=
MW9=
N=
Q=A linear regression line V1 = V6 + V5V0 is computed to predict the final exam score V1 on<br>the basis of the first score V0 on the first test. Suppose V3 scores a V7 on the first<br> test.What would be the predicted value of her score on the final exam?
SA=Answers may vary.
T=M
TF=-1
TL=
TOL=+1E-4
U=NOUNIT
V0=S"<i>x</i>"
V1=S"<i>y</i>"
V10=R.1(V8-3)
V2=I[1,8]
V3=L[V2:Maria,Jenny,Cindy, Robert, Chris, Sean, Jae, Debbie]
V4=S"Cannot be determined"
V5=R.1[0.7,0.9]
V6=I[9,15]
V7=I[50,90,10]
V8=R.1(V7*V5+V6)
V9=R.1(V7*V5)
W=<step>When the first score V0 = V7, the  final exam score would be\nV1 = V6 + V5(V7) = <box>V8</box>.\n</step>
YN=-1
cnum=4
followup=
ilev=0
mcdm=1
mdm=0
mpc=unspecified
mpn=2
mpv=2.0
mwnum=2
ncd=-1
subject=unspecified
varnum=15