A=
AP=<t><c></t>
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ES=Answers may vary.
F0=
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H=$.hint$
INST=
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MS=1
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N=V8
Q=Assume a normally distributed set of test scores with a means of V0 = V1 and a<br>standard deviation of V2.\nFind the probability that a person selected at random\nwill<br>have a score between V3 and V4.\n (Hint: You found the probability that the\nscore will<br>be between V1 and V3 and the probability\nthat the score will be between V1<br> and V4.\nYou should be able to see how to combine these two\nresults to get the desired<br>probability.)<br>$.tablea1$\n
SA=Answers may vary.
T=TL
TF=-1
TL=
TOL=+1E-4
U=NOUNIT
V0=S"$mu$"
V1=I[50,200,10]
V2=I(15*V7)
V3=I(V1+15*V7)
V4=I(V1+30*V7)
V5=S"$sigma$"
V6=S"<i>z</i>"
V7=I[1,5]
V8=R.3(0.475-0.34)
W=<step>\nHere V0 = V1 and V5 = V2.\nV6 =\n<frac>V3 - V1:V2</frac>\n=  <box>1</box>.</step><step>We find the probability that a\nrandomly selected score is between\nthe mean and 1 standard deviation\nabove the mean to be <box>0.34</box>.\n</step>\n<step>V6 =\n<frac>V4 - V1:V2</frac> = <box>2</box>.<br>\n34% + 13.5 % = 47.5% of the scores are within two standard deviations of the mean, so the probability is 47.5% = <box>0.475</box>\n \n</step>\n<step>We found 0.34 to be the\nprobability that a randomly selected score\nis between V1 and V3, and 0.475 to be\nthe corresponding probability for the score\nto be between V1 and V4. Consequently,\nthe probability that the score is between\nV3 and V4 is 0.475 - 0.34 = <box>V8</box>.</step>
YN=-1
cnum=4
followup=
ilev=0
mcdm=1
mdm=0
mpc=unspecified
mpn=2
mpv=2.0
mwnum=2
ncd=-1
subject=unspecified
varnum=13