A=
AP=<t><c></t>
C0=
C1=
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C3=
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C5=
C6=
C7=
C8=
C9=
ES=Answers may vary.
F0=
F1=V10
F2=
H=$.hint$
INST=
M1=
M2=
M3=
M4=
M5=
M6=
M7=
M8=
M9=
MS=1
MW1=
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N=
Q=Assume a normally distributed set\nof test scores with a mean of V0 = V3 and a standard<br>\ndeviation of V4. Find the probability that a person selected at random will have a score<br> V5.<br>$.tablea1$\n
SA=Answers may vary.
T=F
TF=-1
TL=
TOL=+1E-4
U=NOUNIT
V0=S"$mu$"
V1=S"$sigma$"
V10=L[V6:1,0.025]
V11=I(2*V4)
V12=I(V3-V11)
V2=S"<i>z</i>"
V3=I[100,500,10]
V4=I[5,20,5]
V5=L[V6:between V8 and V9, less than V12]
V6=I[1,2]
V7=I(3*V4)
V8=I(V3-V7)
V9=I(V3+V7)
W=<ostep>V6==1::\nThe number of people between <i>u</i> - 3<i>s</i> and <i>u</i> + 3<i>s</i> is 100%, so the probability is <box>100</box>% or <box>1</box>.\n</ostep>\n<ostep>V6==2::\nV2 =\n<frac>V12 - V3:\nV4</frac>\n= <box>-2</box>.</ostep>\n<ostep>V6==2::So V12 is 2 standard deviations\n"below" the mean. Since the probability that such a score is below the mean is 0.5, the probability that the score is below V12 is 0.5 &#8722; 0.475 = <box>0.025</box>.  \n</ostep>
YN=-1
cnum=4
followup=
ilev=0
mcdm=1
mdm=0
mpc=unspecified
mpn=2
mpv=2.0
mwnum=2
ncd=-1
subject=unspecified
varnum=17
commentV3=        //mu