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ES=Answers may vary.
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H=$.hint$
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Q=The daily numbers of pound of garbage for six different households were<p>\n<div=c>V0, V1, V2, V3, V4, V5</div><br>\nFind the range, mean, and standard deviation of the weights.<br>\nRound your answers to two decimal places if necessary.<p>\n<hide>::Range = <box>V11</box><br>\nMean = <box>V14</box><br>\nStandard Deviation =  <box>V31</box><p>\n</hide>
SA=Answers may vary.
T=MI
TF=-1
TL=
TOL=+1E-4
U=NOUNIT
V0=I[10,13]
V1=I[1,3]
V10=
V11=I(V2-V1)
V12=S"<i>x</i>"
V13=E"stack('<small>2</small>','$space:w1h20$')"
V14=I(mean(V0,V1,V2,V3,V4,V5))
V15=E"assert(V16==V14)"
V16=R.12(mean(V0,V1,V2,V3,V4,V5))
V17=I(V0-V14)
V18=I(V1-V14)
V19=I(V2-V14)
V2=I[18,23]
V20=I(V3-V14)
V21=I(V4-V14)
V22=I(V5-V14)
V23=I(pow(V17,2))
V24=I(pow(V18,2))
V25=I(pow(V19,2))
V26=I(pow(V20,2))
V27=I(pow(V21,2))
V28=I(pow(V22,2))
V29=I(V0+V1+V2+V3+V4+V5)
V3=I[4,6]
V30=I(V23+V24+V25+V26+V27+V28)
V31=R.2(ssd(V0,V1,V2,V3,V4,V5))
V4=I[7,9]
V5=I[14,17]
V6=S"$space:w25h1$"
V7=
V8=
V9=
W=<step>Range::=::V2 - <box>V1</box><hide> = V11</hide></step>\n<step>Mean::=::<frac>V0 + V1 + V2 + V3 + V4 + V5:6</frac> = <frac>V29:6</frac> = <box>V14</box></step>\n<step><table>\n<tr><td=c>V6V12V6</td><td=c>V6V12 - $x_bar$V6</td><td=c>V6<paren=11h25>V12 - $x_bar$</paren>V13V6</td></tr>\n<tr><td=C3K0></td></tr>\n<tr><td=c>V0</td><td=c>V17</td><td=c>V23</td></tr>\n<tr><td=c>V1</td><td=c>V18</td><td=c>V24</td></tr>\n<tr><td=c>V2</td><td=c>V19</td><td=c>V25</td></tr>\n<tr><td=c>V3</td><td=c>V20</td><td=c>V26</td></tr>\n<tr><td=c>V4</td><td=c>V21</td><td=c>V27</td></tr>\n<tr><td=c>V5</td><td=c>V22</td><td=c>V28</td></tr>\n<tr><td=C3K0></td></tr>\n<tr><td=c><box>V29</box></td><td=c></td><td=c>V30</td></tr></table></step>\n<step>Standard Deviation::=::<root><frac>V30:5</frac></root> $approx$ <box>V31</box></step>
YN=-1
cnum=4
followup=
ilev=0
mcdm=1
mdm=0
mpc=unspecified
mpn=2
mpv=2.0
mwnum=2
ncd=-1
subject=unspecified
varnum=36