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ES=Answers may vary.
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H=$.hint$
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Q=Out of 20 possible points, a class of 20 students made the following test scores:<p>\n<div=c>V0, V0, V1, V2, V3, V3, V4, V5, V5, V5, V6, V7, V7, V7, V7, V8, V8, V8, V9, V9</div><br>\n<hide>::What is the mode?<br><box>V7</box><p>\nWhat is the median?<br><box>V11</box><p>\nWhat is the mean?<br><box>V13</box><p>\nCalculate the standard deviation to the nearest hundredth.<br><box>V16</box><p>\nWhat percent of scores lie within 1 standard deviation from the mean?<br><box>V42</box>%<p>\nWhat percent of scores lie within 2 standard deviations from the mean?<br><box>100</box>%</hide>\n
SA=Answers may vary.
T=MI
TF=-1
TL=
TOL=+1E-4
U=NOUNIT
V0=I[0,1]
V1=I[2,3]
V10=I(V6+V5)
V11=R.1(V10/2)
V12=I(V0+V0+V1+V2+V3+V3+V4+V5+V5+V5+V6+V7+V7+V7+V7+V8+V8+V8+V9+V9)
V13=I(V12/20)
V14=R.12(V12/20)
V15=E"assert(V13==V14)"
V16=R*.2(ssd(V0,V0,V1,V2,V3,V3,V4,V5,V5,V5,V6,V7,V7,V7,V7,V8,V8,V8,V9,V9))
V17=R.12(V10/2)
V18=E"assert(V11==V17)"
V19=S"<i>x</i>"
V2=I[4,5]
V20=S"<i>n</i>"
V21=R.3(V16*V16)
V22=R.2(V13-V16)
V23=R.2(V13+V16)
V24=R.2(V13+V16)
V25=R.2(V13-V16)
V26=I[1,3]
V27=I[1,3]
V28=L[V26:V0,V1,V2]
V29=L[V27:V9,V8,V7]
V3=I[6,7]
V30=L[V26:V1,V2,V3]
V31=L[V27:V8,V7,V6]
V32=E"assert((V28<V25)&&(V30>V25))"
V33=E"assert((V31<V24)&&(V29>V24))"
V34=L[V26:2,3,4]
V35=L[V27:2,5,9]
V36=I(V34+V35)
V37=R.2((V36/20)*100)
V38=R.2(V13+2*V16)
V39=R.2(V13-2*V16)
V4=I[8,9]
V40=E"assert(V0>V39)"
V41=E"assert(V9<V38)"
V42=I(100-V37)
V43=I(20-V36)
V5=I[10,11]
V6=I[12,13]
V7=I[14,15]
V8=I[16,17]
V9=I[18,20]
W=<step>The mode is the score with the highest frequency: <box>V7</box></step>\n<step>The median is the middle value of the ordered set of numbers.<br>\nmedian = <frac>V6 + V5:2</frac> = <box>V11</box></step>\n<step>Mean = <frac>sum of scores:number of students</frac> = <frac>V12:20</frac> = <box>V13</box></step>\n<step>To find the standard deviation, use the following formula: <root><frac>$sum$(V19 - $x_bar$)^{2}:V20 - 1</frac> </root><br>\nStandard deviation = <root>V21</root> $approx$ <box>V16</box></step>\n<step>To find the percentage of scores within 1 standard deviation of the mean,<br> we need to find the number of scores within V13 - V16 and V13 + V16.  That<br> is, the number of scores between V22 and V23: \n<frac>\nV43:<box>20</box></frac> = V42%</step>\n<step>To find the percentage of scores within 2 standard deviations of the mean,<br> we need to find the number of scores within V13 - 2(V16) and V13 + 2(V16).  That<br> is, the number of scores between V39 and V38: \n<frac>\n20:<box>20</box></frac> = 100%</step>\n
YN=-1
cnum=4
followup=
ilev=0
mcdm=1
mdm=0
mpc=unspecified
mpn=2
mpv=2.0
mwnum=2
ncd=-1
subject=unspecified
varnum=48
commentV22=      //lower bound
commentV23=      //upper bound