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ES=Answers may vary.
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H=$.hint$
INST=The table below shows the distribution of families by income in a particular urban area.
Use the table to answer the following questions. Round all answers to two decimal places.
\n
\n| V0 | V2 |
\n| 0-9,999 | V5 |
\n| 10,000-14,999 | V7 |
\n| 15,000-19,999 | V9 |
\n| 20,000-24,999 | V11 |
\n| 25,000-34,999 | V13 |
\n| 35,000-49,999 | V15 |
\n| 50,000-79,999 | V17 |
\n| 80,000-119,999 | V19 |
\n| 120,000+ | V21 |
\n
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N=
Q=::What proportion of families have incomes of at least $V23?
\nV25\nWhat is the median income range?
\n$V34:0 - 9,999:10,000 - 14,999
\nFind the mean of the lower limits for the annual incomes.
Round to the nearest dollar.
\nV46
\nFind the amount below which V55% of the families have lower incomes.
\n$V56\n
SA=Answers may vary.
T=MI
TF=-1
TL=
TOL=+1E-4
U=NOUNIT
V0=S"Annual Income ($)"
V1=S"Proportion of"
V10=I[25,35]
V11=R*.2(V10/100)
V12=I[5,15]
V13=R*.2(V12/100)
V14=I[9,20]
V15=R*.2(V14/100)
V16=I[1,9]
V17=R*.2(V16/100)
V18=I[1,9]
V19=R*.2(V18/100)
V2=E"stack('V1','V3')"
V20=R*.2(V5+V7+V9+V11+V13+V15+V17+V19)
V21=R*.2(1-V20)
V22=E"assert(V21>0)"
V23=L[V24:10000,15000,20000,25000,35000,50000,80000,120000]
V24=I[1,8]
V25=L[V24:V26,V27,V28,V29,V30,V31,V32,V21]
V26=R*.2(V7+V9+V11+V13+V15+V17+V19+V21)
V27=R*.2(V9+V11+V13+V15+V17+V19+V21)
V28=R*.2(V11+V13+V15+V17+V19+V21)
V29=R*.2(V13+V15+V17+V19+V21)
V3=S"Families"
V30=R*.2(V15+V17+V19+V21)
V31=R*.2(V17+V19+V21)
V32=R*.2(V19+V21)
V33=R*.2(V5+V7+V9)
V34=E"((V33>=0.5)?'15,000 - 19,999':'V36')"
V35=R*.2(V5+V7+V9+V11)
V36=E"((V35>=0.5)?'20,000 - 24,999':'V38')"
V37=R*.2(V5+V7+V9+V11+V13)
V38=E"((V37>=0.5)?'25,000 - 34,999':'V40')"
V39=R*.2(V5+V7+V9+V11+V13+V15)
V4=I[1,12]
V40=E"((V39>=0.5)?'35,000 - 49,999':'V42')"
V41=R*.2(V5+V7+V9+V11+V13+V15+V17)
V42=E"((V41>=0.5)?'50,000 - 79,999':'V44')"
V43=R*.2(V5+V7+V9+V11+V13+V15+V17+V19)
V44=E"((V43>=0.5)?'80,000 - 119,999':'120,000+')"
V45=I(10000+15000+20000+25000+35000+50000+80000+120000)
V46=I(V45/9)
V47=R.2(V5+V7)
V48=I(V47*100)
V49=I(V33*100)
V5=R*.2(V4/100)
V50=I(V35*100)
V51=I(V37*100)
V52=I(V39*100)
V53=I(V41*100)
V54=I(V43*100)
V55=L[V57:V48,V49,V50,V51,V52,V53,V54]
V56=L[V57:15000,20000,25000,35000,50000,80000,120000]
V57=I[1,7]
V58=L[V24:eight items,seven items,six items,five items,four items,three items,two items,item]
V59=L[V57:two,three,four,five,six,seven,eight]
V6=I[1,15]
V60=R*.2(V55/100)
V7=R*.2(V6/100)
V8=I[20,30]
V9=R*.2(V8/100)
W=The sum of the last V58 is V25.\nLocate the range corresponding to 0.50 families,
starting from the top and adding down the list of proportions.\nThus, the median income range is $V34:0 - 9,999:10,000 - 14,999.\nMean of lower income levels:
0 + 10000 + 15000 + 20000 + 25000 + 35000 + 50000 + 80000 + 120000:9 = $V46\nThe sum of the first V59 proportions is V60 which means that
V55% have incomes less than $V56.\n
YN=-1
cnum=4
followup=
ilev=0
mcdm=1
mdm=0
mpc=unspecified
mpn=2
mpv=2.0
mwnum=2
ncd=-1
subject=unspecified
varnum=65