A= AP=a) <1>V16; b)<1>V17 C0= C1= C2= C3= C4= C5= C6= C7= C8= C9= ES=Answers may vary. F0= F1= F2= H=$.hint$ INST=The table gives the numbers of males and females falling into
various salary classifications. Use the table to answer the
following questions. Write your answer as a reduced fraction.

\nV12SalaryV12SexV12TotalsV12\nV12MV12V12FV12\nV12LowV0V1V6V12\nV12AverageV2V3V7V12\nV12HighV4V5V8V12\nV12TotalsV9V10V11V12\n

M1= M2= M3= M4= M5= M6= M7= M8= M9= MS=1 MW1= MW2= MW3= MW4= MW5= MW6= MW7= MW8= MW9= N= Q=Find the probability that a person selected at
random from those surveyed is a female with:
\na) an average income.
\nb) a high income.
\n SA=Answers may vary. T=P TF=-1 TL= TOL=+1E-4 U=NOUNIT V0=I[20,200,10] V1=I[20,300,10:V0] V10=I(V1+V3+V5) V11=I(V9+V10) V12=S"$space:w15h1$" V13=S"P" V14=E"edfrac('V3','V11','improper,yB')" V15=E"edfrac('V5','V11','improper,yB')" V16=E"empfrac('V3','V11','improper')" V17=E"empfrac('V5','V11','improper')" V18=I(V3/10) V19=I(V11/10) V2=I[100,400,10] V20=I(gcd(V18,V19)) V21=E"assert(V20!=1)" V22=I(V5/10) V23=I(gcd(V22,V19)) V24=E"assert(V23!=1)" V3=I[100,400,10:V2] V4=I[200,600,10] V5=I[200,600,10:V4] V6=I(V0+V1) V7=I(V2+V3) V8=I(V4+V5) V9=I(V0+V2+V4) W=a)V12There are V3 favorable outcomes and V11 possible outcomes.\n$space$$space$V12P(female with an average income)::=::V3:V11 = V14\na)V12There are V5 favorable outcomes and V11 possible outcomes.\n$space$$space$V12P(female with a high income)::=::V5:V11 = V15\n YN=-1 cnum=4 followup= ilev=0 mcdm=1 mdm=0 mpc=unspecified mpn=2 mpv=2.0 mwnum=2 ncd=-1 subject=unspecified varnum=29 commentV0= //male low commentV1= //female low commentV10= //female total commentV11= //total commentV2= //male average commentV3= //female average commentV4= //male high commentV5= //female high commentV6= //low total commentV7= //average total commentV8= //high total commentV9= //male total