A=
AP=<t>a)    </t><m><1><t>V10</t></1></m><t>;                                  b)     </t><m><1><t>V17</t></1></m><t> </t>
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ES=Answers may vary.
F0=
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F2=
H=$.hint$
INST=In a survey conducted on a Friday at Quick Shop Supermarket, it was<br> found that V0 out of V1 people who entered the supermarket bought<br> at least 1 item.  Find the probability that a person entering the supermarket<br> on a Friday will purchase <br>
M1=
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MS=1
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N=
Q=a)  at least 1 item.<br>\nb)  no item.<p>\nWrite your answer as a reduced fraction.
SA=Answers may vary.
T=P
TF=-1
TL=
TOL=+1E-4
U=NOUNIT
V0=I[450,850,10]
V1=I[550,990,10]
V10=E"empfrac('V0','V1','improper')"
V11=E"dimproper('V0','V1','d')"
V12=E"dimproper('V0','V1','n')"
V13=I(1*V11)
V14=I(V13-V12)
V15=E"edfrac('V14','V11','improper,yB')"
V16=E"edfrac('V0','V1','improper')"
V17=E"empfrac('V14','V11','improper')"
V2=E"edfrac('V0','V1','improper,yB')"
V3=E"assert(V0<V1)"
V4=S"<i>P</i>"
V5=S"<i>E</i>"
V6=I(V0/10)
V7=I(V1/10)
V8=I(gcd(V6,V7))
V9=E"assert(V8!=1)"
W=<step>There are V0 <box>favorable:possible</box> outcomes and V1 <box>possible:favorable</box> outcomes.</step>\n<step=p>The probability that a person entering the supermarket on a Friday will purchase at least 1 item:</step><step>\nV4(V5)::=::<frac>V0:<box>V1</box></frac> = V2</step> \n<step>P(purchasing no item)::=::<box>1</box> - P(purchasing at least 1 item)</step>\n<step>::=::1 - V16 = V15</step>\n
YN=-1
cnum=4
followup=
ilev=0
mcdm=1
mdm=0
mpc=unspecified
mpn=2
mpv=2.0
mwnum=2
ncd=-1
subject=unspecified
varnum=22